smartOp.modPow2

Equivalent to left % pow(2, exp), but faster and works with a wider range of inputs. This is a safer alternative to left & ((1 << exp) - 1) that is still very fast.

auto modPow2(N left, M exp)
auto modPow2(N left, M exp)
template smartOp(IntFlagPolicy policy)
pure @safe nothrow @nogc
auto
modPow2
(
N
M
)
(
const N left
,
const M exp
)
if (
isFixedPoint!N &&
isFixedPoint!M
)

Examples

import checkedint.sticky : smartOp; // use IntFlagPolicy.sticky

assert(smartOp.modPow2( 101,  1) ==  1);
assert(smartOp.modPow2( 101,  3) ==  5);
assert(smartOp.modPow2(-101,  3) == -5);

assert(smartOp.modPow2(101, -2) ==  0);
assert(smartOp.modPow2(101, 1_000) == 101);

smartOp.modPow2

Examples

Meta

Source