safeOp.modPow2

Equivalent to left % pow(2, exp), but faster and works with a wider range of inputs. This is a safer alternative to left & ((1 << exp) - 1) that is still very fast.

auto modPow2(const N left, const M exp)
auto modPow2(const N left, const M exp)
template safeOp(IntFlagPolicy policy)
auto
modPow2
pure @safe nothrow @nogc
(
N
M
)
(
const N left
,
const M exp
)
if (
isFixedPoint!N &&
isFixedPoint!M
)

Examples

1 import checkedint.sticky : safeOp; // use IntFlagPolicy.sticky
2 
3 assert(safeOp.modPow2( 101,  1) ==  1);
4 assert(safeOp.modPow2( 101,  3) ==  5);
5 assert(safeOp.modPow2(-101,  3) == -5);
6 
7 assert(safeOp.modPow2(101, -2) ==  0);
8 assert(safeOp.modPow2(101, 1_000) == 101);

safeOp.modPow2

Examples

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Source